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Today I encounter a task as follow: I need to extract a 7.3GB Apache access log and ONLY grab the access log starting from 30 August and up to today. I don't need to say it is non-sense to open a 7.3 GB file in a text editor, even in vi under linux, the RAM that is used is huge, and it just doesn't work that way. So to solve this problem, here are the steps I took, thanks to the following reference: -  http://stackoverflow.com/questions/3066948/how-to-file-split-at-a-line-number Find out the exact string first occurrence in the log file and print the first 5 lines.  Actually I can only print one line but I just like 5: grep -n "30/Aug/2015" access_log | head -n 5 The returned line will be: 61445828:203.129.95.51 - - [30/Aug/2015:00:00:01 +0800] "GET <somewebsite>/index.htm HTTP/1.1" 200 10824 The first item: 61445828 is the line number Count the total number of lines in access log, and get the number: wc -l access_log The retur...